Answer:
The value is [tex]v = 2.8 \ m/s[/tex]
Explanation:
From the question we are told that
The depth of the mountain is [tex]d = 0.8 \ m[/tex]
Generally the velocity of the surface wave is mathematically represented as
[tex]v = \sqrt{ g * d }[/tex]
=> [tex]v = \sqrt{ 9.8 * 0.8 }[/tex]
=> [tex]v = 2.8 \ m/s[/tex]
Generally using the Froude number is mathematically represented as
[tex]Fr = \frac{ V }{ v }[/tex]
Here V is the velocity of the current
Given that the waves do not travel upstream, then the flow of the current is supercritical which means that
[tex]\frac{ V }{ v } > 1[/tex]
=> [tex]V > v[/tex]
=> [tex]V > 2.8 \ m/s[/tex]
Hence the minimum velocity of the current is
[tex]v = 2.8 \ m/s[/tex]
This because the velocity of the current is greater velocity of the surface wave , so minimum will be like the lowest possible value of V which is v
