I am trying to get the value of imaginary numbers. The expression is [tex]i^2[/tex]
and now if I evaluate it like this,
[tex]i^2 = (\sqrt{-1} )^2\\= -1[/tex]
I get -1
Again, if I evaluate it like this,
[tex]i^2 = i \times i\\= \sqrt{-1} \times \sqrt{-1}\\= \sqrt{-1 \times -1}\\= \sqrt{1}\\= 1\\[/tex]
I get 1
So there are two values -1 and 1. Which one is correct? If either of these two is incorrect, why?

Respuesta :

Obviously 1 ≠ -1, so both conclusions cannot be true.

The short answer is that √(ab) = √ab is always true if a and b are both non-negative integers, but not always true otherwise. The case here is one in which the identity does not apply. "√a" literally means "the positive number such that its square is a". But you're using the convention that √(-1) = i, and i is not a positive number, so this identity does not apply.

The correct result is i ² = -1.

That's not to say that the identity above is always wrong whenever a or b are not non-negative. For example,

√(-25) = √((-1) × 5²) = √(-1) × √(5²) = 5i