Answer:
The correct option is d: 102 m/s.
Explanation:
The terminal velocity is given by:
[tex]v = \sqrt{\frac{2mg}{\rho AC}}[/tex] (1)
Where:
m: is the mass = 90 kg
g: is the gravity = 9.81 m/s²
A: is the area = 0.14 m²
C: is the drag coefficient = 1.0
ρ: is the density of the air = 1.21 kg/m³
Now, by entering the above values into equation (1) we have:
[tex]v = \sqrt{\frac{2mg}{\rho AC}} = \sqrt{\frac{2*90 kg*9.81 m/s^{2}}{1.21 kg/m^{3}*0.14 m^{2}*1.0}} = 102 m/s[/tex]
Therefore, the correct option is d: 102 m/s.
I hope it helps you!
