The sign's glass absorbed 25466.7 J
Given
The temperature of glass : 23.5 °C to 65.5 °C
mass = 905 g
the specific heat capacity = 0.67 J/g °C
Required
Heat absorbed
Solution
Heat absorbed by sign's glass can be formulated :
[tex]\tt Q=m.c.\Delta T[/tex]
ΔT=65.5 - 23.5 = 42
[tex]\tt Q=905\times 0.67\times 42\\\\Q=\boxed{\bold{25466.7~J}}[/tex]