Answer:
p = - 5, p = - 1
Step-by-step explanation:
Given
[tex]\frac{3p}{p-5}[/tex] - [tex]\frac{2}{p+3}[/tex] = [tex]\frac{p}{p+3}[/tex]
Multiply through by the LCM of (p - 5)(p + 3)
3p(p + 3) - 2(p - 5) = p(p - 5) ← distribute parenthesis
3p² + 9p - 2p + 10 = p² - 5p
3p² + 7p + 10 = p² - 5p ( subtract p² - 5p from both sides )
2p² + 12p + 10 = 0 ← divide through by 2
p² + 6p + 5 = 0 ← in standard form
(p + 1)(p + 5) = 0 ← in factored form
Equate each factor to zero and solve for p
p + 1 = 0 ⇒ p = - 1
p + 5 = 0 ⇒ p = - 5
