Answer: [tex](p+y)(y + z) \\\\[/tex]
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Work Shown:
[tex]py + pz + y^2 + yz \\\\(py + pz) + (y^2 + yz) \\\\p(y + z) + (y*y + yz) \\\\p(y + z) + y(y + z) \\\\(p+y)(y + z) \\\\[/tex]
I grouped the terms into pairs. Then I factored the GCF from each pair
The GCF of py+pz is p
The GCF of y^2+yz is y
On the last line, I factored out the overall GCF (y+z)
You can use the FOIL rule or the distributive property to expand out (p+y)(y+z) and you should get the original expression back again. This is a way to confirm the correct answer.
