Answer:
[CrCl(H₂O)₅]²⁺
Explanation:
Oxidation Number of Chromium = +3
Oxidation Number of Chloride = -1
Oxidation Number of Water molecules = 0
Since the complex contains one chloride atom (Cl), 5 water molecules (H₂O) and one chromium atom (Cr). We have;
CrCl(H₂O)₅
The oxidation number of the mixture is given as;
+3 + (-1) + 5(0) = x
x = + 3 - 1 + 0
x = +2
The chemical formular of the complex is;
[CrCl(H₂O)₅]²⁺
