Answer:
11
Explanation:
the second in the d aray is c because to call the first value, it is d[0]. So, to call c, you put d[2]. And the 0 of the c array, or the 0 of the 2 of the d array, it is 11
put it in a program. I use JS so if you have an Apple, open script editor and change the script from AppleScript to JavaScript and put in this code:
var a = [5, 10, 15];
var b = [2, 4, 6];
var C = [11, 33, 55];
var d = [a, b, C];
d[2][0];
d[2][0] value of your code is 11.
a = [5, 10, 15]
b = [2, 4, 6]
c = [11, 33, 55]
d = [a, b, c]
A variable a is declared and it house an array of numbers 5, 10 and 15.
Variable b is an array of numbers 2, 4 and 6.
Variable c is also an array of numbers 11, 33 and 55.
The last variable d is an array of all the initially declared variables.
Therefore,
d[2][0] simply means we should take d variable and find the index 2(index 2
is c) and get the index 0 of c . The result should be 11 because index zero of
variable c is 11.
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