Answer:
110.9 cm³
Step-by-step explanation:
[tex]V=\frac13\cdot A_b\cdot H[/tex]
[tex]A_b[/tex] - Base Area
H - Height of the pyramid
Base is regular triangle: [tex]A_b=\dfrac{8^2\sqrt3}4[/tex]
The volume:
[tex]V=\dfrac13\times \dfrac{8^2\sqrt3}4\times 12=64\sqrt3\approx110.9[/tex]
