an object is 40M below the surface of sea water of density 1020 kg/m3 calculate the pressure difference

Answer:
P = 400248 [Pa]
Explanation:
We can calculate the hydrostatic pressure exerted by a column of liquid by means of the following equation.
[tex]P=Ro*g*h[/tex]
where:
Ro = density = 1020 [kg/m³]
g = gravity acceleration = 9.81 [m/s²]
h = depth = 40 [m]
Therefore:
[tex]P=1020*9.81*40\\P=400248 [Pa][/tex]