Write an equation in slope-intercept form of the line that passes through the given point and is
perpendicular to the graph of the given equation.
(5,0); y+1=2(x-3)

Respuesta :

Answer:

[tex]y=\frac{-1}{2}x +\frac{5}{2}[/tex]

Step-by-step explanation:

Slope intercept form looks like y=mx+b

The slope (m) needs to be the opposite reciprocal of 2, because the line needs to be perpendicular the given line. Therefore, m = -1/2

We can write the equation in point-slope form first because we're given a point and now we have the slope. The equation would be [tex]y-0=\frac{-1}{2} (x-5)[/tex]

Rewriting, we get [tex]y=\frac{-1}{2}x +\frac{5}{2}[/tex]