Given :
A point ( -3 , -2 ).
An equation of a line, y = x + 2.
To Find :
An equation in slope-intercept form for the line that passes through the given point and is perpendicular to the graph of the given equation.
Solution :
Let, equation of new line is :
y = mx + c ....1)
Here, m and c are slope and intercept respectively.
We know, product of slope of two line is -1 :
m( 1 ) = -1
m = -1
It is also given that point ( -3,-2 ) passes through this point.
Putting value of this point and slope in equation 1), we get :
[tex]-2 = (-1)\times ( -3 ) + c\\\\c = -2 -3\\\\c = -5[/tex]
Therefore, the equation of line is : y = -x -5 .
