The mass of sodium hydrogen carbonate : 10.5 g
Further explanation
Given
1.5 dm' of CO₂
1 mol gas= 24 L at RTP(25 °C, 1 atm)
Required
the mass of sodium hydrogen carbonate
Solution
Decomposition reaction of Sodium hydrogen carbonate :
2 NaHCO₃ (s) ⇒ Na₂
CO₃ (s) + H₂
O(g) + CO₂ (g)
mol CO₂ :
[tex]\tt mol=\dfrac{1.5}{24}=0.0625[/tex]
From the equation, mol ratio of NaHCO₃ : CO₂ (g) = 2 : 1, so mol NaHCO₃ :
[tex]\tt 2\times 0.0625=0.125[/tex]
Mass NaHCO₃(MW=23+1+12+3.16=84 g/mol) :
[tex]\tt mass=mol\times MW\\\\mass=0.125\times 84\\\\mass=10.5[/tex]
