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Express z 1 = 17 [ cos ⁡ ( π ) + i sin ⁡ ( π ) ] z 1 ​ =17[cos(π)+isin(π)]z, start subscript, 1, end subscript, equals, 17, open bracket, cosine, left parenthesis, pi, right parenthesis, plus, i, sine, left parenthesis, pi, right parenthesis, close bracket in rectangular form. Express your answer in exact terms.

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abidemiokin

Answer:

z1 = -17 + 0i

Step-by-step explanation:

Given the complex number z1 ​ =17[cos(π)+isin(π)], we are to express it in rectangular form as shown;

Since cos(π) = -1 and sin(π) = 0, the equation becomes;

z1 ​ =17[cos(π)+isin(π)]

z1 ​ =17[(-1)+i(0)]

z1 = 17(-1 + 0i)

z1 = -17 + 0i

Hence the complex number in rectangular form is expressed as z1 = -17 + 0i

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