Respuesta :

The mass of Aluminum tri bromide that can be made with 5.6 moles of Aluminum is 1,492.90 grams.

What is the relation between mass & moles?

Relation between the mass and moles of any substance will be calculated by using the below equation as:

n = W/M, where

  • W = given mass
  • M = molar mass

Given chemical reaction is:
2Al + 3Br₂ → 2AlBr₃

From the stoichiometry of the reaction, it is clear that:

  • 2 moles of Al = produces 2 moles of AlBr₃
  • 5.6 moles of Al = produces 2 moles of AlBr₃

Now mass of AlBr₃ will be calculated by using the above equation as:

W = (5.6mol)(266.59g/mol) = 1,492.90g

Hence required mass of AlBr₃ is 1,492.90g.

To know more about mass & moles, visit the below link:

https://brainly.com/question/19784089

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