Answer:
The equation in the point-slope form will be:
Step-by-step explanation:
Given
Using the point-slope form of line equation
[tex]y-y_1=m\left(x-x_1\right)[/tex]
here
substituting the values m = 2/3 and the point (-3, 5) in the point-slope form of the line equation
[tex]y-y_1=m\left(x-x_1\right)[/tex]
[tex]y-5=\frac{2}{3}\left(x-\left(-3\right)\right)[/tex]
Thus, the equation in the point-slope form will be:
[tex]y-5=\frac{2}{3}\left(x-\left(-3\right)\right)[/tex]
NOTE: The equation in the point-slope can be further simplified such as:
[tex]y-5=\frac{2}{3}\left(x-\left(-3\right)\right)[/tex]
[tex]y-5=\frac{2}{3}\left(x+3\right)[/tex]
Add 5 to both sides
[tex]y-5+5=\frac{2}{3}\left(x+3\right)+5[/tex]
[tex]y=\frac{2}{3}x+7[/tex]