Hey There!
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Answer:
[tex]\huge\boxed{\text{11.25 grams/mols}}[/tex]
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Reaction:
[tex]2Al_{(s)}+ 3FeO_{(s)} \overset{\Delta} {\Longrightarrow} 3Fe_{(s)}+Al_2O_3_{(s)}[/tex]
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DATA:
Mass of Aluminium: 27 [tex]\frac{gm}{mol}[/tex]
Mass of Ferous Oxide: 71.84 [tex]\frac{gm}{mol}[/tex]
Aluminium: 7.5 Moles Given
How many moles of Iron (II) oxide(FeO)?
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SOLUTION:
As there are 2 moles of aluminium involved and 3 moles of ferrous oxide So,
2 moles Al and 3 moles FeO
7.5 moles Al and x moles FeO
For X moles:
X = [tex]\frac{3\ x\ 7.5 }{2}[/tex]
X= [tex]\frac{22.5}{2}[/tex]
X= 11.25 [tex]\frac{gm}{mol}[/tex]
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Best Regards,
'Borz'
