The empirical formula of the compound is C₃H₄O₂
From the question given above, the following data were obtained:
Carbon = 50.04%
Hydrogen = 5.59%
Oxygen = 44.37%
Divide by their molar mass
C = 50.04 / 12 = 4.17
H = 5.59 / 1 = 5.59
O = 44.37 / 16 = 2.773
Divide by the smallest
C = 4.17 / 2.773 = 1.5
H = 5.59 / 2.773 = 2
O = 2.773 / 2.773 = 1
Multiply by 2 to express in whole number
C = 1.5 × 2 = 3
H = 2 × 2 = 4
O = 1 × 2 = 2
Therefore, the empirical formula of the compound is C₃H₄O₂
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