1) The roots of the equation 9x2 + 3x – 4 = 0 are
A) real, irrational, and unequal
B) real, rational, and unequal
C) imaginary
I
D) real, rational, and equal

Respuesta :

Answer:

D.

Step-by-step equation:

I don't know but i think this is the answer.

The roots of the equation are x = 0.5205 and x = -0.8538. These roots are real, rational and unequal, thus option (B) is the correct answer.

What is a quadratic equation?

A quadratic equation is a polynomial which has the highest degree equal to two. It is a second-degree equation of the form ax² + bx + c = 0, where a, b, are the coefficients, c is the constant term, and x is the variable.

For the given situation,

The equation is 9x^2 + 3x – 4 = 0

The roots of the equation can be found by the formula,

[tex]x=\frac{-b+\sqrt{b^{2}-4ac } }{2a}[/tex] or [tex]x=\frac{-b-\sqrt{b^{2}-4ac } }{2a}[/tex]

here, a = 9, b = 3 and c = -4

Substitute the above values,

⇒ [tex]x=\frac{-3+\sqrt{3^{2}-4(9)(-4) } }{2(9)}[/tex] or  [tex]x=\frac{-3-\sqrt{3^{2}-4(9)(-4) } }{2(9)}[/tex]

⇒ [tex]x=\frac{-3+\sqrt{9+144 } }{18}[/tex]          or  [tex]x=\frac{-3-\sqrt{9+144 } }{18}[/tex]

⇒ [tex]x=\frac{-3+\sqrt{153 } }{18}[/tex]             or  [tex]x=\frac{-3-\sqrt{153 } }{18}[/tex]

⇒ [tex]x=\frac{-3+12.36 }{18}[/tex]             or  [tex]x=\frac{-3-12.36 }{18}[/tex]

⇒ [tex]x=\frac{9.37}{18}[/tex]                    or  [tex]x=\frac{-15.37}{18}[/tex]

⇒ [tex]x=0.5205[/tex]                or  [tex]x=-0.8538[/tex]

Hence we can conclude that the roots of the equation are x = 0.5205 and x = -0.8538. These roots are real, rational and unequal, thus option (B) is the correct answer.

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