A person walks first at a constant speed of 2 m/s along a straight line from point A to point B and then back along the line from B to A at a constant speed of 4 m/s. What is the average speed (in m/s) over the entire trip?

Respuesta :

Answer:

The average speed is 2.67 m/s

Explanation:

Constant Speed Motion

The speed of a moving object can be calculated as:

[tex]\displaystyle v=\frac{x}{t}[/tex]

Where

x = distance

t = time

Solving for t:

[tex]\displaystyle t=\frac{x}{v}[/tex]

The average speed is calculated as:

[tex]\displaystyle \bar v=\frac{x_t}{t_t}[/tex]

Where xt and tt are the total distance and time respectively.

The person walks at a constant speed of v1=2 m/s for a distance x. They take a time t1 to travel calculated by:

[tex]\displaystyle t_1=\frac{x}{v_1}[/tex]

Then, the person walks back at v2=4 m/s the same distance x. Thus, the second time is:

[tex]\displaystyle t_2=\frac{x}{v_2}[/tex]

The total time taken for the entire travel is:

[tex]\displaystyle t_t=\frac{x}{v_1}+\frac{x}{v_2}[/tex]

Simplifying and substituting:

[tex]\displaystyle t_t=\frac{x}{2}+\frac{x}{4}[/tex]

[tex]\displaystyle t_t=\frac{2x}{4}+\frac{x}{4}[/tex]

[tex]\displaystyle t_t=\frac{3x}{4}[/tex]

The total distance is xt=2x, thus the average speed is:

[tex]\displaystyle \bar v=\frac{2x}{\frac{3x}{4}}[/tex]

Simplifying:

[tex]\displaystyle \bar v=\frac{8}{3}=2.67[/tex]

The average speed is 2.67 m/s