Answer:
Presumably you're solving for x here? Without further information we'll assume that.
With that in mind, x is approximately equal to 0.86 and -0.46
Step-by-step explanation:
Let's start by putting it in the usual ax² + bx + c format.
[tex]5x^2- 2x = 2\\5x^2 - 2x - 2 = 0\\[/tex]
let's solve it. First we'll multiply both sides by five, making the first term a perfect square:
[tex]25x^2 - 10x - 10 = 0\\[/tex]
Now we'll add 11 to both sides:
[tex]25x^2 - 10x + 1 = 11\\[/tex]
Which makes the left side a perfect square:
[tex](5x - 1)^2 = 11[/tex]
And now we can solve for x:
[tex](5x - 1)^2 = 11\\\\5x - 1 = \sqrt{11} \\\\5x = 1 + \sqrt{11}\\\\x = \frac{1 + \sqrt{11}}{5}[/tex]
Note that there's no apparent way of drawing the ± symbol when editing equations, so take that + sign as actually being ±.
That gives us two answers:
[tex]x = \frac{1 + \sqrt{11}}{5}\\\\x \approx \frac{1 + 3.32}5\\\\x \approx \frac{4.32}5\\\\x \approx 0.86[/tex] [tex]x = \frac{1 - \sqrt{11}}{5}\\\\x \approx \frac{1 - 3.32}5\\\\x \approx \frac{-2.32}5\\\\x \approx -0.46[/tex]
