Answer:
0.97 atm ≅ 1 atm
Explanation:
The relation between the pressure (P) and volume (V) of a gas is given by the Boyle's law. According to this, the volume is inversely proportional to the pressure:
P₁ x V₁ = P₂ x V₂
From the problem, we have:
V₁= 400.0 mL x 1 L/1000 mL = 0.4 L
P₁= 5.2 atm
V₂= 2.14 L
We calculate the final pressure (P₂) from the equation, as follows:
P₂ = (P₁ x V₁)/V₂ = (5.2 atm x 0.40 L)/ 2.14 L = 0.97 atm ≅ 1 atm
Therefore, as the volume is increased (from 0.4 L to 2.14 L), the pressure in decreased (from 5.2 atm to 0.97 atm).
A 400.0-mL can contains compressed gas at 5.2 atm. The gas is sprayed into a bag, that inflates to 2.14 L at 0.97 atm.
Boyle's law states that the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature.
A 400.0-mL can contains compressed gas at 5.2 atm. The gas is sprayed into a bag, that inflates to 2.14 L. We can calculate the final pressure of the gas using Boyle's law.
P₁ × V₁ = P₂ × V₂
P₂ = P₁ × V₁ / V₂
P₂ = 5.2 atm × 0.4000 L / 2.14 L = 0.97 atm
where,
A 400.0-mL can contains compressed gas at 5.2 atm. The gas is sprayed into a bag, that inflates to 2.14 L at 0.97 atm.
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