A piece of paper has a rectangle ABCD in which AB= 10 cm and BC = 22 cm , it was folded to form a right circular cylinder such that AB is cincident to DC . Find the volume of the resulted cylinder

Respuesta :

Answer:  [tex]385cm^{2}[/tex]

Step-by-step explanation:

given data:

AB= 10 cm.

BC = 22 cm.

volume of a cylinder V = [tex]\pi r^{2} h[/tex]

h = 10.

solution

base of the circumference = 22cm

circumference of a circle = [tex]2\pi r[/tex]

r = radius is unknown.

[tex]2\pi r = 22[/tex] .........................eq1

where [tex]\pi = \frac{22}{7}[/tex] insert this into eq1.

[tex]2* \frac{22}{7}* r = 22[/tex]

[tex]\frac{44}{7} r = 22[/tex]

[tex]r = \frac{22}{\frac{44}{7} }[/tex]

[tex]r= 3.5cm[/tex]

next we solve for the volume of the cylinder.

recall   [tex]V = \pi r^{2} h[/tex]

h = 10cm

r = 3.5cm

[tex]V = \frac{22}{7} * (3.5)^{2} *10[/tex]

[tex]V = 385cm^{2}[/tex]