What current in a solenoid 15-cm long wound with 100 turns would produce a magnetic field equal to that of the Earth, 5 cross times 10 to the power of negative 5 end exponentT ?

Respuesta :

Answer:

The value is  [tex]I= 0.0597\ A[/tex]  

Explanation:

From the question we are told that

    The length of the solenoid is [tex]l = 15 \ cm = 0.15 \ m[/tex]

     The number of turns is  [tex]N = 100[/tex]

      The  magnetic field of the earth is  [tex]B = 5* 10^{-5} \ T[/tex]

Gnerally magnetic field is mathematically represented as

          [tex]B = \frac{\mu_o * N * I }{ l }[/tex]

=>        [tex]I= \frac{Bl}{ \mu_o *N }[/tex]

=>        [tex]I= \frac{ 5 *10^{-5} * 0.15}{4\pi *10^{-7} *100 }[/tex]  

=>        [tex]I= 0.0597\ A[/tex]