The volume = 309.04 ml
Further explanation
Given
Specific gravity=-1.28 and strength =24.7% by mass of H₂SO₄
mass 125g of ZnC0₃
Required
The volume of H₂SO₄ Solution
Solution
Reaction
ZnCO₃ + H₂SO₄ → ZnSO₄ + CO₂ + H₂O
mol of ZnCO₃(MW=125.4 g/mol) :
[tex]\tt mol=\dfrac{125}{125.4}=0.997[/tex]
From equation, mol ZnCO₃ : H₂SO₄= 1 : 1 so mol H₂SO₄=0.997
mass of H₂SO₄ (MW=98 g/mol) :
[tex]\tt mass=mol\times MW=0.997\times 98=97.706~g[/tex]
mass of solution :
[tex]\tt \dfrac{100}{24.7}\times 97.706=395.57~g[/tex]
Volume of solution :(density of solution=1.28 g/ml for the reference substance is water(density=1 g/ml)
[tex]\tt V=\dfrac{395.57}{1.28}=309.04~ml[/tex]
