Answer: You want to find the equation for a line that passes through the point (-6,1) and has a slope of 13.
First of all, remember what the equation of a line is:
y = mx+b
Where:
m is the slope, and
b is the y-intercept
To start, you know what m is; it's just the slope, which you said was 13. So you can right away fill in the equation for a line somewhat to read:
y=13x+b.
Now, what about b, the y-intercept?
To find b, think about what your (x,y) point means:
(-6,1). When x of the line is -6, y of the line must be 1.
Because you said the line passes through this point, right?
Now, look at our line's equation so far: . b is what we want, the 13 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (-6,1).
So, why not plug in for x the number -6 and for y the number 1? This will allow us to solve for b for the particular line that passes through the point you gave!.
(-6,1). y=mx+b or 1=13 × -6+b, or solving for b: b=1-(13)(-6). b=79
Step-by-step explanation:
