Answer:
The container can hold 22 gallons of water.
Step-by-step explanation:
Let 'g' be the number of gallons a container can hold
- Given the initial amount of water = 1/6 g
Given that 11 gallons of water have been added to the container.
- so the final quantity will become = 2/3 g
Thus, the equation becomes
[tex]\frac{2}{3}g-\frac{1}{6}g=11[/tex]
Multiply by LCM 6
[tex]\frac{2}{3}g\cdot \:6-\frac{1}{6}g\cdot \:6=11\cdot \:6[/tex]
[tex]4g-g=66[/tex]
[tex]3g=66[/tex]
Divide both sides by 3
[tex]\frac{3g}{3}=\frac{66}{3}[/tex]
[tex]g=22[/tex]
Therefore, the container can hold 22 gallons of water.
