contestada

A jet aircraft is traveling at 219 m/s in horizontal flight. The engine takes in air at a rate of 77.9 kg/s and burns fuel at a rate of 4.19 kg/s. The exhaust gases are ejected at 934 m/s relative to the aircraft. Find the thrust of the jet engine. Answer in units of N. 019 (part 2 of 2) 10.0 points Find the delivered power. Answer in units of W

Respuesta :

ebrightosagie

Answer: thrust [tex]-85905.24N[/tex]

delivered power [tex]= -18813247.56W[/tex]

Explanation:

given data:

horizontal speed = 219 m/s

rate of air intake = 77.9 kg/s

fuel combustion rate = 4.19 kg/s.

exhaust gases ejected = 934 m/s

solutuon:

Thrust of the engine

[tex]Fth = Ve * ( Mf - Ma ) - Vj *Ma[/tex]

[tex]= 934 * ( 4.19 - 77.9 ) - 219 *77.9[/tex]

[tex]= -68845.14 - 17060.1[/tex]

=[tex]-85905.24N[/tex]

delivered power

[tex]= Fth * Vj[/tex]

[tex]= -85905.24N * 219[/tex]

[tex]= -18813247.56W[/tex]

Cricetus

The delivered power will be "-18813247.56 W".

Given:

  • Horizontal speed = 219 m/s
  • Rate of air = 44.9 kg/s
  • Fuel combustion rate = 4.19 kg/s
  • Exhaust gas ejected = 934 m/s

Thrust of the engine will be:

→ [tex]F^{th} = Ve(Mf-Ms)-Vj\times Ma[/tex]

By putting the values, we get

         [tex]= 934(4.19-77.9)-219\times 77.9[/tex]

         [tex]= -68845.14-17060.1[/tex]

         [tex]= -85905.24 \ N[/tex]

hence,

The delivered power will be:

= [tex]F^{th}\times Vj[/tex]

= [tex]-85905.24\times 219[/tex]

= [tex]-18813247.56 \ W[/tex]

Thus the solution above is right.

Learn more about power here:

https://brainly.com/question/20695102

Otras preguntas