Respuesta :
Amount after n years = original amount x interest^(number of years)
30,000 = A x (1.05)²⁰
A = $11,307
30,000 = A x (1.05)²⁰
A = $11,307
Answer: She would need to put approximately $ 11306.684 into the account in order to have $30,000 at the end of 20 years.
Step-by-step explanation:
Let P be the amount of the money she need to put into the account,
Since, the annual rate of interest = 5%
Time = 20 years
Hence, with this compound interest the amount she got after 20 years,
[tex]A=P(1+\frac{5}{100})^{20}[/tex]
[tex]\implies A = P(1+0.05)^{20}\implies A = P(1.05)^{20}[/tex]
According to the question,
A = $ 30,000
[tex]\implies P(1.05)^{20} = 30000[/tex]
[tex]\implies P\times 2.65329770514 = 30000[/tex]
[tex]\implies P = 11306.6844862\approx 11306.684[/tex]
Hence, She would need to put approximately $ 11306.684 into the account in order to have $30,000 at the end of 20 years