This one too!!! This is from the same project that I was struggling with and was similar to the other problem but I couldn't figure it out.

This one too This is from the same project that I was struggling with and was similar to the other problem but I couldnt figure it out class=

Respuesta :

9514 1404 393

Answer:

  y = 1/4x^1 -x -4

Step-by-step explanation:

Same question as previous parts. The working is identical, using different numbers.

Focus-vertex distance is (y-difference) p = -4-(-5) = 1. Vertex is (h, k) = (2, -5). Putting these values into the vertex form and expanding to standard form, you get ...

  y = (1/(4p))(x -h)^2 +k

  y = 1/4(x -2)^2 -5 . . . . . . . . fill in the values for p, h, k

  y = 1/4(x^2 -4x +4) -5 . . . .  expand the square

  y = 1/4x^2 -x +1 -5 . . . . . . . use the distributive property to eliminate parens

  y = 1/4x^1 -x -4 . . . . . . . . . collect terms

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Additional information may be found at ...

  https://brainly.com/question/20338735