Respuesta :

Answer:

4x² + 12xy + 9y²

Step-by-step explanation:

Assuming you require the expansion

(2x + 3y)²

= (2x + 3y)(2x + 3y)

Each term in the second factor is multiplied by each term in the first factor, that is

2x(2x + 3y) + 3y(2x + 3y) ← distribute both parenthesis

= 4x² + 6xy + 6xy + 9y² ← collect like terms

= 4x² + 12xy + 9y²

rosh18

Answer:

[tex] {4x}^{2} + 12y + {9y}^{2} [/tex]

Step-by-step explanation:

[tex](2x + 3y) {}^{2} \\ {(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2} \\ = {(2x)}^{2} + 2 \times 2x \times 3y + {(3y)}^{2} \\ = 4 {x}^{2} + 12y + 9 {y}^{2} \\ hope \: it \: helps[/tex]

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