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Two ships leave the port at 12 noon. Ship A is traveling at the bearing of 146 at 20 miles per hour, and ship B travels at a bearing of N32 E at 28 miles per hour. Approximate how far apart ships are at 3 PM. At what bearing ship A is from ship B at 3 PM.

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ebrightosagie

Answer: [tex]d = 103.23 miles[/tex] apart.

Step-by-step explanation:

given data:

ship a = 20miles. = 60miles

ship b = 28miles. = 84miles

time interval = 3hrs.

θ = 90

[tex]d = \sqrt{a^{2}+b^{2}-2ab (cos90) }[/tex]

[tex]d = \sqrt{60^{2}+84^{2}-2(60)(84) *(cos90) }[/tex]

[tex]d = \sqrt{3600+7056-10080*(cos90) }[/tex]

[tex]d = \sqrt{10656-10080*(cos90) }[/tex]

[tex]d = \sqrt{10656-0[/tex]

[tex]d = \sqrt{10656[/tex]

[tex]d = 103.23 miles[/tex]

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