9514 1404 393
Answer:
C) √3
Step-by-step explanation:
The repeating decimals are both single digits, beginning at the decimal point. So, their equivalent is that digit divided by 9:
[tex]0.\overline{4}=\dfrac{4}{9}\\\\0.\overline{9}=\dfrac{9}{9}=1[/tex]
This means the given expression can be simplified to ...
[tex]\dfrac{3\sqrt{0.\overline{4}}+\sqrt{0.\overline{9}}}{\sqrt{3}}=\dfrac{3\sqrt{\dfrac{4}{9}}+\sqrt{\dfrac{9}{9}}}{\sqrt{3}}=\dfrac{3\cdot\dfrac{2}{3}+1}{\sqrt{3}}=\dfrac{3}{\sqrt{3}}=\boxed{\sqrt{3}}[/tex]
