Respuesta :

Proof:

In [tex]\triangle MNP[/tex] and [tex]\triangle OPN[/tex]:

[tex]MN = OP[/tex] (given)

[tex]MP = ON[/tex] (given)

[tex]NP[/tex] (common)

[tex]\therefore \triangle MNP \cong \triangle OPN[/tex] (SSS)

[tex]\therefore[/tex] [tex]\angle M \cong \angle O[/tex] since they are corresponding angles of congruent triangles.

Hope this helps :)