Answer:
The value is [tex]k = 2 \ ppb[/tex]
Explanation:
From the question we are told that
The volume of the drinking water is [tex]V = 500 \ mL = 500 *10^{-3} \ L = 500 *10^{-6} \ m^3[/tex]
The mass of mercury it contains [tex]m_c = 0.001 \ mg = 0.001 *10^{-3} \ g = 0.001 *10^{-6}\ kg[/tex]
Generally the mass of water is mathematically represented as
[tex]m = V * \rho[/tex]
Here [tex]\rho[/tex] is the density of water with value [tex]\rho = 1000 \ kg/m^3[/tex]
So
[tex]m = 500 *10^{-6 }* 1000[/tex]
=> [tex]m = 0.5 \ kg[/tex]
Generally ppb mean part per billon , and 1 billon is 100,000,000
So the part per billon which this represents is mathematically represented as
[tex]k = \frac{0.001 *10^{-6}}{ 0.5} * 100 000 000[/tex]
=> [tex]k = 2 \ ppb[/tex]
