mol fraction Codein : 0.054
mol fraction Ethanol : 0.946
Given
46.85 g of codeine
125.5 g of ethanol
Required
mol fraction
Solution
The mole fraction : the mole ratio of a substance to the mole of solution /mixture
mol Codeine, C₁₈H₂₁NO₃(MW=299.4 g/mol) :
[tex]\tt mol=\dfrac{46.85}{299.4 g/mol}\\\\mol=0.1565[/tex]
mol Ethanol, C₂H₅OH(MW=46.07 g/mol)
[tex]\tt mol=\dfrac{125.5}{46.07}=2.7241[/tex]
mol of solution :
[tex]\tt mol~codein+mol~ethanol=0.1565+2.7241=2.8806[/tex]
[tex]\tt \dfrac{0.1565}{2.8806}=0.054[/tex]
mol fraction Ethanol :
[tex]\tt \dfrac{2.7241}{2.8806}=0.946[/tex]
