Answer:
The 95% confidence interval estimate of the proportion of people who say that they voted
(0.67122 , 0.72798)
Step-by-step explanation:
Step(i):-
In a recent survey of 1002 people, 701 said that they voted in a recent presidential election.
Sample proportion
[tex]p = \frac{x}{n} = \frac{701}{1002} = 0.6996[/tex]
Step(ii)
The 95% confidence interval estimate of the proportion of people who say that they voted
[tex](p^{-} - Z_{0.05} \sqrt{\frac{p(1-p)}{n} } , p^{-} + Z_{0.05} \sqrt{\frac{p(1-p)}{n} } )[/tex]
[tex](0.6996 - 1.96\sqrt{\frac{0.6996(1-0.6996)}{1002} } , 0.6996 + 1.96 \sqrt{\frac{0.6996(1-0.6996)}{1002} } )[/tex]
(0.6996 - 1.96 X 0.01448 , 0.6996 + 1.96 X 0.01448)
(0.6996 - 0.02838 , 0.6996 + 0.02838)
(0.67122 , 0.72798)
Final answer:-
The 95% confidence interval estimate of the proportion of people who say that they voted
(0.67122 , 0.72798)
