Answer:
0.43478
Step-by-step explanation:
From the information given:
[tex]The \ required \ probability = P(1st ball = red) \times P(2nd ball = red) + P(1st ball = red) \times P(2nd ball = white) + P(2nd ball = red) \times P(1st ball = white) + P(1st ball = white) \times P(2nd ball = white)[/tex]
[tex]= \dfrac{6}{6+8+10}\times \dfrac{5}{5+8+10} + \dfrac{6}{6+8+10} \times \dfrac{10}{5+8+10} + \dfrac{10}{6+8+10} \times \dfrac{6}{5+8+10} \times \dfrac{10}{6+8+10} \times \dfrac{9}{5+8+9}[/tex]
[tex]=(\dfrac{6}{24}\times \dfrac{5}{23})+ (\dfrac{6}{24}\times \dfrac{10}{23}) +( \dfrac{10}{24}\times \dfrac{6}{23} ) + (\dfrac{10}{24}\times \dfrac{9}{23})[/tex]
= 0.05434782609 + 0.1086956522 + 0.1086956522 + 0.1630434783
= 0.4347826088
≅ 0.43478
