Answer:
The frequency heard by the observer is 24,830.35 Hz.
Explanation:
Given;
frequency of the source, Fs = 18,002 Hz
speed of the source, Vs = 130
speed of sound in air, V = 343 m/s
Apply Doppler effect, as the source and the observer move closer to each other, the frequency heard by the observer increases because of decrease in distance.
[tex]f_s = f_o[\frac{v}{v + v_s} ]\\\\[/tex]
where;
f₀ is the frequency heard by the observer
[tex]f_s = f_o[\frac{v}{v + v_s} ]\\\\18,002 = f_o[\frac{343}{343 + 130} ]\\\\18,002 = f_o(0.725)\\\\f_o = \frac{18,002}{0.725} \\\\f_o = 24,830.35 \ Hz[/tex]
Therefore, the frequency heard by the observer is 24,830.35 Hz.
