Answer:
The appropriate response will be "125.55 kg/hr".
Explanation:
The given values are:
Rate of heat exchanger,
m = 1000 kg/h
Inlet temperature,
T = 30°C
Specific heat,
[tex]c_p[/tex] = 4 kJ/(kg°C)
Now,
The heat taken by juice from steam will be:
⇒ [tex]Q=mc_p(\Delta T)[/tex]
On substituting the values, we get
⇒ [tex]=1000\times 4(100-30)[/tex]
⇒ [tex]=280000 \ kJ/hr[/tex]
The heat given by the steam to juice will be:
⇒ [tex]Q=m\times L[/tex]
On substituting the values, we get
⇒ [tex]=m\times 125.55[/tex]
On equating both the heat values, we get
⇒ [tex]280000=m\times 2230.2[/tex]
⇒ [tex]m=\frac{280000}{2230.2}[/tex]
⇒ [tex]m=125.55 kg/hr[/tex]
