ladybb
contestada

the length of a rectangle is twice the width. the perimeter is 36feet. find the length time width

Respuesta :

HeavenlyHelper

Let the length of the rectangle be L and the width be W.

Given that the length is twice the width, Then :


L = 2W .....(1)

But we know that the perimeter is 36.

==> 2L + 2W = 36

==> 2L + L = 36

==> 3L = 36

==> L = 36/3 = 12

==> W = 12/2 = 6

Now we will calculate the area:

==> A = L * W = 12* 6 = 72 square feet.

Then the area of the rectangle is 72 square feet.


SkyWorks
What do you know?: The Length Is Twice the Width
Write an equation: l = 2w
What else do you know?: The Perimeter is 36
Write and equation: P = 2l + 2w >>> 36 = 2l + 2w
Divide 36 by 3: 36 / 3 = 12
Put 12 in for w: l = 2(12) >>> l = 24
The Length is 24, and the Width is 12.

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