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A cyclist is riding his bike up a mountain trail. When he starts up the trail, he is going 8 m/s. As the trail gets steeper, he slows to 3 m/s in 1 minute. What is the cyclist’s acceleration?

Respuesta :

-0.08 m/s^2 , just answered this question

Answer:

The cyclist's acceleration is -0.08 m/s².

Explanation:

Given that,

Speed [tex]v_{i} = 8\ m/s[/tex]

Speed [tex]v_{f}= 3\ m/s[/tex]

Time = 1 sec

We know that,

The formula of acceleration is defined as:

[tex]a = \dfrac{v_{f}-v_{i}}{t}[/tex]

Where, a = acceleration

[tex]v_{f}[/tex]= final speed

[tex]v_{i}[/tex]= initial speed

We substitute the value into formula

[tex]a = \dfrac{3-8}{60}[/tex]

[tex]a= \dfrac{-5}{60}[/tex]

[tex]a = -0.08 m/s^2[/tex]

Hence, The cyclist's acceleration is -0.08 m/s².

     

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