Respuesta :
for
ax+by=c
the slope is -a/b
20x+25y≥200
slope=-20/25=-4/5
negative slope
yint is where x=0
20(0)+25y≥200
25y≥200
y≥98
positive yint
x+y<10
slope=-1/1=-1
yint is where x=0
y<10
yint is at y=10
since it is equal, it is solid line
to tell if it is above then sub (0,0) and see if true
0≥200
false
shade on side that doesn't have (0,0), shade above line
x+y<10 doesn't have equal under so it is dashed
test (0,0)
0<10
true, it is shaded below
test point (4,5)
20(4)+25(5)≥200
80+125≥200
225≥200
true
4+5<10
9<10
true
so the ones that are true are
The line x + y < 10 has a negative slope and a positive y-intercept.
The line representing 20x + 25y ≥ 200 is solid and the graph is shaded above the line.
The overlapping region contains the point (4, 5).
ax+by=c
the slope is -a/b
20x+25y≥200
slope=-20/25=-4/5
negative slope
yint is where x=0
20(0)+25y≥200
25y≥200
y≥98
positive yint
x+y<10
slope=-1/1=-1
yint is where x=0
y<10
yint is at y=10
since it is equal, it is solid line
to tell if it is above then sub (0,0) and see if true
0≥200
false
shade on side that doesn't have (0,0), shade above line
x+y<10 doesn't have equal under so it is dashed
test (0,0)
0<10
true, it is shaded below
test point (4,5)
20(4)+25(5)≥200
80+125≥200
225≥200
true
4+5<10
9<10
true
so the ones that are true are
The line x + y < 10 has a negative slope and a positive y-intercept.
The line representing 20x + 25y ≥ 200 is solid and the graph is shaded above the line.
The overlapping region contains the point (4, 5).
The line x + y < 10 has a negative slope and a positive y-intercept. The line representing 20x + 25y ≥ 200 is solid and the graph is shaded above the line. The overlapping region contains the point (4, 5). Options 2,3 and 4 are correct.
What is the equation?
A mathematical statement consisting of an equal symbol between two algebraic expressions with the same value is known as an equation.
The standard equation is;
ax+by=c
The slope of the standard equation is;
m= -a/b
The inequality equation found for the given condition;
20x+25y≥200
The slope of the linear equality;
m₁ = -20/25
m₁= -4/5
The obtained slope for the inequality is negative.
To obtain the value of substitute x=0
20(0)+25y≥200
25y≥200
y≥98
The value of y is positive.
Condition 2;
x+y<10
The slope of the inequality;
m₂ = =-1/1
m₂=-1
Value of y when the x is equal to zero.
y=10
Check for the condition by substuting the value of x and y as the 4 and 5;
20(4)+25(5)≥200
80+125≥200
225≥200
The corect statement obtained as a conclusion ;
2. The line x + y < 10 has a negative slope and a positive y-intercept.
3. The line representing 20x + 25y ≥ 200 is solid and the graph is shaded above the line.
4. The overlapping region contains the point (4, 5).
Hence,options 2,3 and 4 are correct.
To learn more, about equations, refer;
https://brainly.com/question/10413253
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