Respuesta :
for
ax^2+bx+c
the axis of symmetry is -b/2a
first one
-3/2=3, nope
2nd one
3/2=3? nope
3rd one
-6/2=3? nope
fourth
6/2=3? yes
answer is last one or
f(x)=x^2-6x-1
ax^2+bx+c
the axis of symmetry is -b/2a
first one
-3/2=3, nope
2nd one
3/2=3? nope
3rd one
-6/2=3? nope
fourth
6/2=3? yes
answer is last one or
f(x)=x^2-6x-1
Answer:
Option 4th is correct
[tex]f(x) = x^2-6x-1[/tex]
Step-by-step explanation:
A quadratic equation is in the form of: [tex]y=ax^2+bx+c[/tex].....[1]; then the axis of symmetry is given by:
[tex]x = \frac{-b}{2a}[/tex]
As per the statement:
To find :
The graph of which function has an axis of symmetry at x = 3
From the given options:
Option 4th is the graph of a function which has axis of symmetry at x = 3
Consider a function:
[tex]f(x) =x^2-6x-1[/tex]
On comparing with [1] we have;
a = 1 and b = -6
then;
[tex]x = \frac{-(-6)}{2 \cdot 1}[/tex]
⇒[tex]x = \frac{6}{2} =3[/tex]
Therefore, The graph of which function has an axis of symmetry at x = 3 is, [tex]f(x) = x^2-6x-1[/tex]