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There are 64 squares on a checkerboard. bobby puts one penny on the first square, two on the second square, four on the third, eight on the fourth, and continues to double the number of coins at each square until he has covered all 64 squares. how many coins must he place upon the last square? a- 2^64 b- 2^63 c- 2^64 - 1 d- 2^64 - 2 e- 2^63 1

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apologiabiology
ok so
first one is 1
2nd is 2
3rd is 4

so
an=a1(r^(n-1))
a1=first term
r=common ratio
n=which term

frst term is 1
common ratio is 2

n=64

a64=1(2^(64-1))
a64=2^63


B would be the answer

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