An unknown substance has a mass of 14.7 g . When the substance absorbs 1.323×102 J of heat, the temperature of the substance is raised from 25.0 ∘C to 45.0 ∘C . What is the most likely identity of the substance?

A. aluminum 0.903
B. iron 0.449
C. water 4.184
D. silver 0.235
E. copper 0.385
F. ethanol 2.42

The correct answer of the given question above would be option B. IRON 0.449. Based on the given details above about an unknown substance that has a mass of 14.7 g and the substance absorbs 1.323×102 J of heat, the temperature of the substance is raised from 25.0 ∘C to45.0 ∘C, most likely, the substance is IRON. Hope this answers the question.

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Alleei Alleei · Answer 2 · 2019-09-18T08:01:37+02:00

Answer : The correct option is, (B) iron 0.449

Explanation :

Formula used :

[tex]Q=m\times c\times \Delta T\\\\Q=m\times c\times (T_2-T_1)[/tex]

where,

Q = heat absorb = [tex]1.323\times 10^2J[/tex]

m = mass of substance = 14.7 g

c = specific heat of substance = ?

[tex]\Delta T[/tex] = change in temperature

[tex]T_1[/tex] = initial temperature = [tex]25^oC[/tex]

[tex]T_2[/tex] = final temperature = [tex]45^oC[/tex]

Now put all the given value in the above formula, we get:

[tex]1.323\times 10^2J=14.7g\times c\times (45-25)^oC[/tex]

[tex]c=0.45J/g^oC[/tex]

Form the value of specific heat of substance, we conclude that the metal used in this was iron.

Therefore, the correct option is (B) iron 0.449