Respuesta :
Answer: Twice the previous time would be taken to reach the same speed v with the puck of mass 2m.
Explanation:
Let a Force pushes the hockey puck of mass m.
Then acceleration, [tex]a= \frac{F}{m}[/tex]
From the equation of motion,
[tex]\Rightarrow v=u+at\\ v=0+\frac{F}{m}\Delta t[/tex] ......(1)
In the second case, when mass is 2m, then acceleration,
[tex]a'=\frac{F}{2m}[/tex]
and t' is the time taken.
The final speed is v,
[tex]\Rightarrow v=0+ a't'\\ \Rightarrow \frac {F}{m}\Delta t=\frac{F}{2m}t'\\ \Rightarrow t'= 2\Delta t[/tex] using equation (1)
Hence, it would take two times the previous amount of time to push the pluck of double mass.
