ok
distance formula
D=[tex] \sqrt{(x1-x2)^2+(y1-y2)^2} [/tex]
given
distance between (-6,5) and (-3,y) is 5
5=[tex] \sqrt{(-6-(-3))^2+(5-y)^2} [/tex]
5=[tex] \sqrt{(-6+3)^2+(5-y)^2} [/tex]
5=[tex] \sqrt{(-3)^2+(5-y)^2} [/tex]
5=[tex] \sqrt{9+y^2-10t+25} [/tex]
5=[tex] \sqrt{y^2-10t+34} [/tex]
square both sides
25= [tex] y^2-10t+34 [/tex]
minus 25 both sides
[tex] 0= y^2-10t+9 [/tex]
factor
0=(y-9)(y-1)
set to zero
0=y-9
9=y
0=y-1
1=y
the points are (-3,1) and (-3,9)
