Answer :
The ordered pairs for the equation are (0,-3), (1,-2.5), (6,0), (8,1).
Step by step explanation:
Given : Equation [tex]y=\frac{1}{2}x-3[/tex]
To find : Make a table of ordered pairs for the equation ?
Solution :
To make a table we use different value of x and y for which equation satisfied.
Taking different values of x and y,
For x=0,
[tex]y=\frac{1}{2}(0)-3=-3[/tex]
For x=1,
[tex]y=\frac{1}{2}(1)-3=-\frac{5}{2}=-2.5[/tex]
For y=0,
[tex]0=\frac{1}{2}x-3[/tex]
[tex]x=6[/tex]
For y=1,
[tex]1=\frac{1}{2}x-3[/tex]
[tex]x=8[/tex]
Write in table form,
x | 0 | 1 | 6 | 8 |
y | -3 | -2.5 | 0 | 1 |
The ordered pairs for the equation are (0,-3), (1,-2.5), (6,0), (8,1).
