Respuesta :
d = \/(0-(-2))² + (-6-4)²
d = \/(0+2)² + (-10)²
d = \/(2² + 100)
d = \/(4+100)
d = \/104
d ~ 10,20
d = \/(0+2)² + (-10)²
d = \/(2² + 100)
d = \/(4+100)
d = \/104
d ~ 10,20
The distance from (-2, 4) to (0, -6) is approximately 10.20 units.
Given two distinct points [tex]P_{1}[/tex] and [tex]P_{2}[/tex], the distance between these points is determined by straight line length formula:
[tex]d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}[/tex] (1)
Where [tex]d[/tex] is the straight line distance between points [tex]P_{1}[/tex] and [tex]P_{2}[/tex].
If we know that [tex]P_{1} = (-2, 4)[/tex] and [tex]P_{2} = (0, -6)[/tex], then the straight line distance between points [tex]P_{1}[/tex] and [tex]P_{2}[/tex]:
[tex]d = \sqrt{[0-(-2)]^{2}+(-6-4)^{2}}[/tex]
[tex]d \approx 10.198[/tex]
The distance from (-2, 4) to (0, -6) is approximately 10.20.
We kindly invite to see this question on straight line distances: https://brainly.com/question/1156725